2F47 hexadecimal to binary

Here we will show you how to convert the hexadecimal number 2F47 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert 2F47 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in 2F47 by 16⁰, multiply the second to last digit in 2F47 by 16¹, multiply the third to last digit in 2F47 by 16², multiply the fourth to last digit in 2F47 by 16³, and so on, until all the digits are used.

7 × 16⁰ = 7
4 × 16¹ = 64
F × 16² = 3840
2 × 16³ = 8192

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

7 + 64 + 3840 + 8192 = 12103

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

12103 ÷ 2 = 6051 with 1 remainder
6051 ÷ 2 = 3025 with 1 remainder
3025 ÷ 2 = 1512 with 1 remainder
1512 ÷ 2 = 756 with 0 remainder
756 ÷ 2 = 378 with 0 remainder
378 ÷ 2 = 189 with 0 remainder
189 ÷ 2 = 94 with 1 remainder
94 ÷ 2 = 47 with 0 remainder
47 ÷ 2 = 23 with 1 remainder
23 ÷ 2 = 11 with 1 remainder
11 ÷ 2 = 5 with 1 remainder
5 ÷ 2 = 2 with 1 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 2F47 hexadecimal to binary:

2F47 hexadecimal = 10111101000111 binary

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2F48 hexadecimal to binary
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