28B hexadecimal to binary

Here we will show you how to convert the hexadecimal number 28B to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert 28B from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in 28B by 16⁰, multiply the second to last digit in 28B by 16¹, multiply the third to last digit in 28B by 16², multiply the fourth to last digit in 28B by 16³, and so on, until all the digits are used.

B × 16⁰ = 11
8 × 16¹ = 128
2 × 16² = 512

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

11 + 128 + 512 = 651

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

651 ÷ 2 = 325 with 1 remainder
325 ÷ 2 = 162 with 1 remainder
162 ÷ 2 = 81 with 0 remainder
81 ÷ 2 = 40 with 1 remainder
40 ÷ 2 = 20 with 0 remainder
20 ÷ 2 = 10 with 0 remainder
10 ÷ 2 = 5 with 0 remainder
5 ÷ 2 = 2 with 1 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 28B hexadecimal to binary:

28B hexadecimal = 1010001011 binary

Hexadecimal to Binary Converter
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