23C5 hexadecimal to binary

Here we will show you how to convert the hexadecimal number 23C5 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert 23C5 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in 23C5 by 16⁰, multiply the second to last digit in 23C5 by 16¹, multiply the third to last digit in 23C5 by 16², multiply the fourth to last digit in 23C5 by 16³, and so on, until all the digits are used.

5 × 16⁰ = 5
C × 16¹ = 192
3 × 16² = 768
2 × 16³ = 8192

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

5 + 192 + 768 + 8192 = 9157

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

9157 ÷ 2 = 4578 with 1 remainder
4578 ÷ 2 = 2289 with 0 remainder
2289 ÷ 2 = 1144 with 1 remainder
1144 ÷ 2 = 572 with 0 remainder
572 ÷ 2 = 286 with 0 remainder
286 ÷ 2 = 143 with 0 remainder
143 ÷ 2 = 71 with 1 remainder
71 ÷ 2 = 35 with 1 remainder
35 ÷ 2 = 17 with 1 remainder
17 ÷ 2 = 8 with 1 remainder
8 ÷ 2 = 4 with 0 remainder
4 ÷ 2 = 2 with 0 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 23C5 hexadecimal to binary:

23C5 hexadecimal = 10001111000101 binary

Hexadecimal to Binary Converter
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