22B4 hexadecimal to binary




Here we will show you how to convert the hexadecimal number 22B4 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).


The four steps used to convert 22B4 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in 22B4 by 16⁰, multiply the second to last digit in 22B4 by 16¹, multiply the third to last digit in 22B4 by 16², multiply the fourth to last digit in 22B4 by 16³, and so on, until all the digits are used.

4 × 16⁰ = 4
B × 16¹ = 176
2 × 16² = 512
2 × 16³ = 8192

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

4 + 176 + 512 + 8192 = 8884

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

8884 ÷ 2 = 4442 with 0 remainder
4442 ÷ 2 = 2221 with 0 remainder
2221 ÷ 2 = 1110 with 1 remainder
1110 ÷ 2 = 555 with 0 remainder
555 ÷ 2 = 277 with 1 remainder
277 ÷ 2 = 138 with 1 remainder
138 ÷ 2 = 69 with 0 remainder
69 ÷ 2 = 34 with 1 remainder
34 ÷ 2 = 17 with 0 remainder
17 ÷ 2 = 8 with 1 remainder
8 ÷ 2 = 4 with 0 remainder
4 ÷ 2 = 2 with 0 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 22B4 hexadecimal to binary:

22B4 hexadecimal = 10001010110100 binary


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