
Here we will show you how to convert the hexadecimal number 1E58 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).
The four steps used to convert 1E58 from hexadecimal to binary are explained below.
Step 1)
Multiply the last digit in 1E58 by 16⁰, multiply the second to last digit in 1E58 by 16¹, multiply the third to last digit in 1E58 by 16², multiply the fourth to last digit in 1E58 by 16³, and so on, until all the digits are used.
8 × 16⁰ = 8
5 × 16¹ = 80
E × 16² = 3584
1 × 16³ = 4096
Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.
Step 2)
Next, we add up all the products we got from Step 1, like this:
8 + 80 + 3584 + 4096 = 7768
Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.
7768 ÷ 2 = 3884 with 0 remainder
3884 ÷ 2 = 1942 with 0 remainder
1942 ÷ 2 = 971 with 0 remainder
971 ÷ 2 = 485 with 1 remainder
485 ÷ 2 = 242 with 1 remainder
242 ÷ 2 = 121 with 0 remainder
121 ÷ 2 = 60 with 1 remainder
60 ÷ 2 = 30 with 0 remainder
30 ÷ 2 = 15 with 0 remainder
15 ÷ 2 = 7 with 1 remainder
7 ÷ 2 = 3 with 1 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder
Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 1E58 hexadecimal to binary:
1E58 hexadecimal = 1111001011000 binary
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1E59 hexadecimal to binary
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