1A9B hexadecimal to binary

Here we will show you how to convert the hexadecimal number 1A9B to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert 1A9B from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in 1A9B by 16⁰, multiply the second to last digit in 1A9B by 16¹, multiply the third to last digit in 1A9B by 16², multiply the fourth to last digit in 1A9B by 16³, and so on, until all the digits are used.

B × 16⁰ = 11
9 × 16¹ = 144
A × 16² = 2560
1 × 16³ = 4096

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

11 + 144 + 2560 + 4096 = 6811

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

6811 ÷ 2 = 3405 with 1 remainder
3405 ÷ 2 = 1702 with 1 remainder
1702 ÷ 2 = 851 with 0 remainder
851 ÷ 2 = 425 with 1 remainder
425 ÷ 2 = 212 with 1 remainder
212 ÷ 2 = 106 with 0 remainder
106 ÷ 2 = 53 with 0 remainder
53 ÷ 2 = 26 with 1 remainder
26 ÷ 2 = 13 with 0 remainder
13 ÷ 2 = 6 with 1 remainder
6 ÷ 2 = 3 with 0 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 1A9B hexadecimal to binary:

1A9B hexadecimal = 1101010011011 binary

Hexadecimal to Binary Converter
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