1A53 hexadecimal to binary

Here we will show you how to convert the hexadecimal number 1A53 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert 1A53 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in 1A53 by 16⁰, multiply the second to last digit in 1A53 by 16¹, multiply the third to last digit in 1A53 by 16², multiply the fourth to last digit in 1A53 by 16³, and so on, until all the digits are used.

3 × 16⁰ = 3
5 × 16¹ = 80
A × 16² = 2560
1 × 16³ = 4096

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

3 + 80 + 2560 + 4096 = 6739

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

6739 ÷ 2 = 3369 with 1 remainder
3369 ÷ 2 = 1684 with 1 remainder
1684 ÷ 2 = 842 with 0 remainder
842 ÷ 2 = 421 with 0 remainder
421 ÷ 2 = 210 with 1 remainder
210 ÷ 2 = 105 with 0 remainder
105 ÷ 2 = 52 with 1 remainder
52 ÷ 2 = 26 with 0 remainder
26 ÷ 2 = 13 with 0 remainder
13 ÷ 2 = 6 with 1 remainder
6 ÷ 2 = 3 with 0 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 1A53 hexadecimal to binary:

1A53 hexadecimal = 1101001010011 binary

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1A54 hexadecimal to binary
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