
Here we will show you how to convert the hexadecimal number 1947 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).
The four steps used to convert 1947 from hexadecimal to binary are explained below.
Step 1)
Multiply the last digit in 1947 by 16⁰, multiply the second to last digit in 1947 by 16¹, multiply the third to last digit in 1947 by 16², multiply the fourth to last digit in 1947 by 16³, and so on, until all the digits are used.
7 × 16⁰ = 7
4 × 16¹ = 64
9 × 16² = 2304
1 × 16³ = 4096
Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.
Step 2)
Next, we add up all the products we got from Step 1, like this:
7 + 64 + 2304 + 4096 = 6471
Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.
6471 ÷ 2 = 3235 with 1 remainder
3235 ÷ 2 = 1617 with 1 remainder
1617 ÷ 2 = 808 with 1 remainder
808 ÷ 2 = 404 with 0 remainder
404 ÷ 2 = 202 with 0 remainder
202 ÷ 2 = 101 with 0 remainder
101 ÷ 2 = 50 with 1 remainder
50 ÷ 2 = 25 with 0 remainder
25 ÷ 2 = 12 with 1 remainder
12 ÷ 2 = 6 with 0 remainder
6 ÷ 2 = 3 with 0 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder
Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 1947 hexadecimal to binary:
1947 hexadecimal = 1100101000111 binary
Hexadecimal to Binary Converter
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1948 hexadecimal to binary
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